Himeno and Mustang

So I recently shared a pin-up of Yor for her second-place prize in a recent popularity polling tournament on my Discord. The first place in that tournament was Himeno, and this is her prize.
The first place in these tournaments always gets to work with a character of their choosing, provided it’s someone they haven’t appeared with before. This is meant to be an in-character choice, and I balanced a few options I thought Himeno might go with. In the end, she decided to go with Roy Mustang.
Mustang’s known as quite the heartthrob, and I think he fits well into Himeno’s tastes. I also liked using this to set up a bit of a relationship between Himeno and Hawkeye. I’m not sure what exactly it is, but I find the idea of those two being friends really appealing. So here’s Himeno’s first place prize!

Yor Forger Superstar Pose

A little while ago on my Subscriber Discord, we wrapped up another one of our long-running popularity poll tournaments. Like always, the winner of the tournament will get a scene coming up soon, and the runner-up gets a pin-up. Yor was our runner-up, so here she is. Since she also got a Vanguard pic not too long ago I tried to pose her a bit differently and show off a different side than in that one.

Amy Wong Character Ask 1

Mars is a planet we love to populate in fiction, but of course every story has its own idea of what Martians would be like. Amy is a Martian in that she lives on Mars, but she’s still a human. Futurama has its own Native Martians that she would be familiar with, however, although they’re mostly just coded like Native Americans.
While I was able to think of a handful of notable Martian characters, within the Studio the main one who came to mind was Queen Tyr’ahnee, the Queen of Mars from Duck Dodgers. The only other character I could think of was, like, Sailor Mars maybe, but it’s possible I’m forgetting some other characters with Martian roots. Even if I thought of someone else, though, I love Tyr’ahnee so I probably would’ve gone with her as Amy’s partner regardless.